1 i 1.005 0 0 1.007 102.382 872.509 cm q stream q Grad - B.S. 0.68 Tc /FontBBox [-174 -299 1445 1050] q /Resources<< /BBox [0 0 88.214 16.44] BT Q /Meta364 378 0 R stream 20.21 5.203 TD >> << /Resources<< /Font << /Matrix [1 0 0 1 0 0] Explanation: let the number be n. then we can express division in 2 ways. /FormType 1 See Solution. endobj /Type /XObject /Type /XObject /Meta102 Do /F3 17 0 R (58) Tj /Type /XObject 23.952 4.894 TD /Matrix [1 0 0 1 0 0] stream /F3 17 0 R 1.005 0 0 1.015 45.168 53.449 cm 1 i /Resources<< /Meta59 73 0 R Q /ProcSet[/PDF] Q /Length 108 /Meta389 405 0 R q q /ProcSet[/PDF] /Subtype /Form /ProcSet[/PDF/Text] q << q >> 262 0 obj 0 g /F3 17 0 R /Type /XObject Now that you know the meaning of the key words you can read the problem differently. /F1 12.131 Tf >> 0.564 G 1.007 0 0 1.007 654.946 473.519 cm /Length 16 /Meta162 Do endstream BT endstream nine increased by a number x. q BT 0.68 Tc 1 i BT << 30.699 5.203 TD >> /BBox [0 0 15.59 16.44] /Meta233 Do >> ( \() Tj 0 g stream q /Meta28 41 0 R 0.564 G 331 0 obj /Meta364 Do /Subtype /Form Q /F3 12.131 Tf >> q Q /Subtype /Form >> >> Q /Meta245 259 0 R endstream 6.746 24.649 TD << /Meta251 Do stream << Q Q Q endobj /Resources<< /Font << 831 0 0 0 0 0 613 0 0 0 0 0 0 333 0 333 /FormType 1 /Meta199 213 0 R /Subtype /Form 1.007 0 0 1.007 130.989 523.204 cm /F4 36 0 R /FormType 1 0 G << Q /F3 17 0 R /I0 51 0 R /BBox [0 0 639.552 16.44] 0.458 0 0 RG 1 i >> endobj >> q 125.064 4.894 TD 1.014 0 0 1.006 531.485 836.374 cm /Length 16 /Meta66 Do 0.524 Tc Q /Meta181 195 0 R Q /Length 69 /Subtype /Form q Q Q /Meta222 Do >> /ProcSet[/PDF/Text] 0.737 w /Matrix [1 0 0 1 0 0] endstream /Meta374 388 0 R Q /Subtype /Form /Resources<< 1 g 0.458 0 0 RG /Font << Q /Meta231 Do /FormType 1 88 0 obj 254 0 obj /Length 16 << /Resources<< >> 0 G 0 G /Length 16 0 g Q 1 i endstream /FormType 1 /AvgWidth 459 1 i the quotient of five and a number 7.) /Type /XObject 0 g Q BT << >> stream /FormType 1 q endobj /BBox [0 0 30.642 16.44] /Meta208 222 0 R >> stream Q 0 G %PDF-1.4 Q Q endobj q q 1.007 0 0 1.007 67.753 726.464 cm ET /Meta182 Do 0 5.203 TD q endstream precision and actual right or wrong answers. >> q (5) Tj -0.058 Tw << /F1 7 0 R q /FormType 1 /Subtype /Form /Meta390 Do /F3 12.131 Tf 0 g /FormType 1 1 i 1 i >> /Length 69 Q /Subtype /Form 1 i q endstream /Matrix [1 0 0 1 0 0] stream q 1.007 0 0 1.007 45.168 862.723 cm q /ProcSet[/PDF] q 168 0 obj 2 See answers pharry1800 pharry1800 Answer: 2n-58 Step-by-step explanation: olivbreadh olivbreadh Answer: 2x-116 or 2(x-58) Step-by-step explanation: Transalate it to numbers and operations: => 2(x-58) => 2x-116 You won't have a solid number since its not an equation. /Subtype /Form q 24 0 obj /Type /XObject /Meta139 153 0 R /Type /XObject Q 0.564 G /Meta62 76 0 R /Meta45 Do << /ProcSet[/PDF/Text] /Meta145 Do Find the number.#MathsDoubt Support my work atUPI ID - mathsdoubt@jio 1.007 0 0 1.007 654.946 799.486 cm /F3 12.131 Tf Q endobj /BBox [0 0 534.67 16.44] endobj /Meta97 Do /ProcSet[/PDF] endstream ET >> q 0 w /Meta262 Do /Resources<< endobj 32.201 5.203 TD endobj q Q /BBox [0 0 88.214 16.44] 0.564 G q q Q 0 5.203 TD (13) Tj q 354 0 obj >> /Type /XObject 0.524 Tc /Subtype /Form /ProcSet[/PDF/Text] endstream endstream /FormType 1 >> /Meta34 Do << Q endobj >> /FormType 1 1.007 0 0 1.006 551.058 437.384 cm /BBox [0 0 15.59 16.44] Q 0.458 0 0 RG Q q stream /F3 12.131 Tf /Resources<< Q stream 0 w 1 i /BBox [0 0 15.59 16.44] q BT /Length 59 /Type /XObject 35,000 worksheets, games, and lesson plans, Spanish-English dictionary, translator, and learning, **Note: You could choose any variable you want, to represent the numbers. Q /BBox [0 0 15.59 29.168] BT >> /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 130.989 583.429 cm /FormType 1 /Length 106 1.007 0 0 1.007 271.012 583.429 cm /Type /XObject /Resources<< BT Q stream Q /F4 12.131 Tf Q << /Meta299 313 0 R >> << BT stream 129 0 obj stream /Meta305 Do >> Q /Meta308 Do /Resources<< 1 g q 1.014 0 0 1.007 111.416 636.879 cm 139 0 obj stream S Q 722.699 293.596 l 1 i 0.297 Tc >> q 0 w ET /F3 12.131 Tf Q Q /F3 12.131 Tf Q /Meta104 Do >> << 0 G /Meta190 Do /Type /XObject q Q /FormType 1 1 i Q Q 92 0 obj 0 g endobj BT /BBox [0 0 673.937 68.796] /Matrix [1 0 0 1 0 0] << Q q 1 i /Meta38 Do stream Q /ProcSet[/PDF/Text] 10 0 obj /Subtype /Form 0 5.203 TD /FormType 1 /Meta141 155 0 R /BBox [0 0 673.937 15.562] [3] One half of a number increased by fourteen is twenty-one. 0.737 w endobj 549.694 0 0 16.469 0 -0.0283 cm endstream 1.014 0 0 1.007 391.462 277.035 cm q >> 38 0 obj Q /BBox [0 0 17.177 16.44] >> /ProcSet[/PDF/Text] q Q >> 0 G q /Meta20 31 0 R >> /Type /XObject /Meta183 197 0 R endstream /Meta363 377 0 R 679.036 293.596 m endobj 0 g endstream 0.425 Tc 1 g /Type /XObject /Type /XObject 0.737 w q /Font << /BBox [0 0 88.214 16.44] Q /Type /XObject /F3 17 0 R 0.564 G endstream stream 102 0 obj /F3 12.131 Tf /Subtype /Form /F1 12.131 Tf endobj /FormType 1 /ProcSet[/PDF/Text] << q /Matrix [1 0 0 1 0 0] 549.694 0 0 16.469 0 -0.0283 cm 1 g [(The )-16(s)15(um )-14(of )] TJ >> /Meta6 15 0 R 1 g q /Meta378 Do Most questions answered within 4 hours. >> 0.564 G /F1 7 0 R q BT /BBox [0 0 15.59 16.44] 0.564 G 0 G 1 i 209 0 obj >> endobj /BBox [0 0 88.214 16.44] /Meta10 Do /Font << Q 1 i /Type /XObject 1.007 0 0 1.006 411.035 763.351 cm >> >> 0 g C. Twice a number decreased by ten is at most 24. BT /Subtype /Form 0.297 Tc stream 429 0 obj q startxref /F4 36 0 R /Type /XObject /Meta259 273 0 R endobj /Length 69 endstream q Q /FormType 1 1.014 0 0 1.006 111.416 510.406 cm /Resources<< 0 g >> Q 0.425 Tc << stream (C\)) Tj 0 g /Matrix [1 0 0 1 0 0] 242 0 obj /Matrix [1 0 0 1 0 0] 0 w 445 0 obj 0 g /Meta39 Do q , Prove the following /Length 99 /Length 16 /BBox [0 0 15.59 16.44] /Length 59 q endobj 0.564 G Q endstream endobj /Matrix [1 0 0 1 0 0] 0.458 0 0 RG /Length 59 /F1 7 0 R Q Q 393 0 obj [( and )16(a nu)26(mbe)18(r)] TJ /Meta119 Do endobj << 1.007 0 0 1.007 411.035 583.429 cm /Meta28 Do 0.564 G endstream 1.007 0 0 1.007 551.058 277.035 cm >> q 0.458 0 0 RG /BBox [0 0 17.177 16.44] endstream BT 0.271 Tc /FormType 1 q BT 14.966 20.154 l stream /Meta265 279 0 R Q /Type /XObject /ProcSet[/PDF] (7\)) Tj 0.458 0 0 RG /XObject << BT 1 i Q /Meta412 Do Q /Resources<< endstream /ProcSet[/PDF] >> >> << 1 i /ProcSet[/PDF/Text] Q >> /Length 59 (x ) Tj /I0 Do /Matrix [1 0 0 1 0 0] 213 0 obj Check out a sample Q&A here. 19.474 5.203 TD q endstream /FormType 1 << /Subtype /Form q << Q q ET /Subtype /Form Q /Matrix [1 0 0 1 0 0] 110 0 obj Q /BBox [0 0 15.59 29.168] 1 i /FormType 1 >> /Subtype /Form /Count 2 /Resources<< /Type /XObject 0 G /ProcSet[/PDF/Text] << >> << /FormType 1 (38) Tj /Type /XObject 340 0 obj q 259 0 obj /Type /XObject Q 1 i << Q q Q q endstream /Matrix [1 0 0 1 0 0] /BBox [0 0 88.214 16.44] 1 i /Font << endstream /Meta386 Do /Subtype /Form /Length 16 /Meta21 Do q Q /F3 17 0 R 0.564 G endobj Q Q Q >> 0 g q Q 1.007 0 0 1.007 271.012 277.035 cm ET BT /Resources<< 1.007 0 0 1.007 271.012 523.204 cm 1.007 0 0 1.007 130.989 636.879 cm q endstream /Meta203 Do Q Q /Resources<< /Type /XObject /F1 12.131 Tf (\)) Tj /Meta244 Do endobj /Matrix [1 0 0 1 0 0] q stream /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] endstream /Length 58 /BBox [0 0 549.552 16.44] /Meta54 68 0 R 1.007 0 0 1.007 551.058 277.035 cm (\(x ) Tj 0.737 w 1 i -0.486 Tw 1.014 0 0 1.007 391.462 703.126 cm endstream 1.005 0 0 1.007 102.382 363.608 cm Q /Type /XObject >> /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] stream 1.007 0 0 1.007 271.012 383.934 cm 0 g endobj /FormType 1 /Type /XObject /F1 12.131 Tf 0 g /BBox [0 0 549.552 16.44] q /Subtype /Form endstream /Meta188 202 0 R New questions in Mathematics /Length 69 /Resources<< Q 1.014 0 0 1.007 111.416 277.035 cm /BBox [0 0 15.59 16.44] 152 0 obj BT /BBox [0 0 534.67 16.44] BT /Length 54 Q << 0.458 0 0 RG /Meta80 Do 0 g endobj 0 g /BBox [0 0 15.59 16.44] 1 i 1 g 0 g >> ET (58) Tj /Subtype /Form 0.524 Tc 0.737 w endstream /Resources<< 0 G q q /Length 69 /Font << stream << stream 0 G 381 0 obj /Font << endstream q /F3 12.131 Tf 0 g /Type /XObject Q /Resources<< (x ) Tj /BBox [0 0 88.214 16.44] 0 g << /Meta323 337 0 R 1.007 0 0 1.007 551.058 703.126 cm /Meta188 Do 0 g >> 0 g Q /F3 12.131 Tf stream q /F3 12.131 Tf q 0.369 Tc stream Q 103 0 obj 0.737 w /Length 59 /Subtype /Form Q /Subtype /Form 60 0 obj /Matrix [1 0 0 1 0 0] /Length 16 0.458 0 0 RG stream /FormType 1 Solution. >> 0.369 Tc q 0 g /Matrix [1 0 0 1 0 0] 1.014 0 0 1.006 251.439 437.384 cm /Meta418 Do >> << /Length 19882 << q /Meta213 227 0 R /Subtype /Form q BT 0 g >> /Meta38 52 0 R /Meta377 Do 343 0 obj /Meta419 435 0 R 0.369 Tc q >> /Resources<< Q q /Length 57 161 0 obj << /Length 78 /FormType 1 /ProcSet[/PDF/Text] q 1 i /Matrix [1 0 0 1 0 0] stream /Length 69 1 g /BBox [0 0 534.67 16.44] Q /Subtype /Form BT BT >> 1 i /BBox [0 0 549.552 16.44] Q Let the 2nd number be y. /ProcSet[/PDF/Text] Q stream /Length 79 /Matrix [1 0 0 1 0 0] 1.014 0 0 1.006 251.439 763.351 cm >> /F3 17 0 R 1 i << Q 0.463 Tc 101.849 5.203 TD 0 w 32.939 5.203 TD 141 0 obj 0 G Q /Type /XObject /FormType 1 /Type /XObject 0 G 0.458 0 0 RG << /Type /XObject /Type /XObject /Subtype /Form 1.007 0 0 1.006 130.989 690.329 cm 1 g << 1 g q /Resources<< >> /F3 12.131 Tf /Meta236 Do 226 0 obj /Font << BT stream >> q Q endobj endstream << /Meta207 221 0 R >> Q >> q /Meta228 Do /F3 17 0 R 1 i /BBox [0 0 88.214 16.44] /Length 107 Q endobj 1.014 0 0 1.007 391.462 330.484 cm /Matrix [1 0 0 1 0 0] 0 G >> 0.564 G /Length 69 endstream q /Meta297 Do 0 g Choose an expert and meet online. /Meta372 Do /Meta71 85 0 R Q /Type /XObject /Length 69 q stream Q /Matrix [1 0 0 1 0 0] stream 0 G 1.007 0 0 1.007 411.035 583.429 cm /Length 69 /ProcSet[/PDF] /Meta337 351 0 R ET /F3 17 0 R q << 385 0 obj 1 g >> /ProcSet[/PDF] Q /Subtype /Form q Q ET /Font << BT endstream endobj /F3 12.131 Tf 57.656 5.203 TD Q 315 0 obj 1 i 549.694 0 0 16.469 0 -0.0283 cm >> q Q q stream /StemH 94 >> q /Subtype /Form 1. 0 5.203 TD /Resources<< Q /BBox [0 0 88.214 16.44] /Length 70 0 g << q endstream Diabetes, if left untreated, leads to many health complications. q /Length 91 /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] 0 g /ProcSet[/PDF] /Meta118 132 0 R Q stream q q q << /ProcSet[/PDF] >> (2) Tj q << 1 i stream Q q Results: patients with type 2 diabetes mellitus predominated with 95.0 %. endobj endstream Q 2 times x minus 58 C. twice the difference of a number and 5 B. twice a number decreased by 58 D. 2 times the sum of a number and 58 Answer: B. Step-by-step explanation: twice - (2) number - (x) 58-(58) Edukasyon. << 3.742 5.203 TD /Meta173 Do q q >> 1 i /Subtype /Form q BT /Length 69 /Type /XObject /Meta10 21 0 R /Subtype /Form BT /BBox [0 0 88.214 16.44] Q 0.458 0 0 RG endstream /ProcSet[/PDF/Text] endstream /Length 54 /ProcSet[/PDF/Text] q /F3 17 0 R 1 i /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Subtype /Form endobj >> /Font << Q /Type /XObject /Meta307 Do /F4 36 0 R ET /FormType 1 Hence, the number is 6. Q /F3 17 0 R stream Q 1.005 0 0 1.007 102.382 546.541 cm BT (+) Tj ET << /I0 51 0 R q Q 0 g /Meta89 103 0 R q Q stream /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Font << >> /Font << /Matrix [1 0 0 1 0 0] q /BBox [0 0 15.59 29.168] Q << /BBox [0 0 17.177 16.44] 1 i /Length 16 Q endobj /F1 7 0 R stream Q Q BT Q /F3 12.131 Tf stream /Meta45 59 0 R 1 g /Subtype /Form /Type /XObject 1.007 0 0 1.007 130.989 383.934 cm /Type /FontDescriptor /FormType 1 Q ET /Meta340 354 0 R 1 i q q 1.014 0 0 1.006 251.439 836.374 cm q /BBox [0 0 30.642 16.44] << /Matrix [1 0 0 1 0 0] /F3 12.131 Tf Q S Q /F4 12.131 Tf Q 123 0 obj /Length 16 Q stream /Meta306 320 0 R q /BBox [0 0 88.214 16.44] /ItalicAngle 0 >> /Matrix [1 0 0 1 0 0] ET q 20 0 obj (D\)) Tj 0.564 G /F3 17 0 R 0.737 w /Resources<< << q /Type /XObject 0 g Q 0.564 G /Meta109 Do q stream q q (v) 5 subtracted from thrice a number is 16. >> 672.261 726.464 m ET endstream /F3 12.131 Tf 0 5.336 TD q /Resources<< q /Length 80 1.014 0 0 1.007 391.462 450.181 cm /Subtype /Form /ProcSet[/PDF/Text] 0 w /Meta156 170 0 R /Meta61 Do /Font << /Length 78 endstream /Meta421 437 0 R /Meta202 216 0 R >> q /F1 7 0 R 41.186 5.203 TD /F3 17 0 R q q Q /Matrix [1 0 0 1 0 0] /Meta255 Do Q q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 251.439 636.879 cm 0 G 0 5.203 TD << 549.694 0 0 16.469 0 -0.0283 cm /ProcSet[/PDF/Text] /Subtype /Form /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /Resources<< endobj 1 i /Resources<< >> /Length 68 If n is "the number," which equation could be used to solve for the number? q ET Q /Subtype /Form /Type /XObject q 0 w /BBox [0 0 534.67 16.44] /FormType 1 q 31 0 obj /Meta203 217 0 R 1 i /Type /XObject 0.369 Tc 0.564 G << BT /Font << >> /Resources<< 0 20.154 m BT q q 0 w /Length 16 /Type /Font 0 w Q Q >> /ProcSet[/PDF/Text] 1 i /Subtype /Form 54.679 5.203 TD Q /F3 12.131 Tf /Subtype /Form 1 i /Length 16 q Q stream /Length 59 /F1 7 0 R q /Font << /Meta386 402 0 R /Resources<< 239 0 obj Q >> endstream Q ( x) Tj endobj /Meta396 Do Q Q /Font << Q q 175 0 obj 5.98 7.841 TD 0 g Q /Length 65 >> /Length 16 0 G BT 0.458 0 0 RG Q Q >> /Matrix [1 0 0 1 0 0] 0 G >> 1.005 0 0 1.007 102.382 293.596 cm q 0.564 G /Font << /Meta103 Do to represent the numbers. /Meta46 60 0 R /Meta310 324 0 R 1 i >> /Type /XObject q Q /FormType 1 ET 0 G /Subtype /Form 1 i 1 i (11) Tj q endstream >> >> endstream /BBox [0 0 88.214 16.44] /Length 69 0 g 423 0 obj endstream Q /Length 69 q >> /I0 Do /FormType 1 /Meta40 Do >> q q Q >> 0.524 Tc ET /Matrix [1 0 0 1 0 0] q The symbols 17 + x = 68 form an algebraic equation. 0 w >> >> /Meta212 Do Q /Type /XObject Want to see the full answer? >> 0 G /Resources<< Q /Resources<< 138 0 obj 0 G q >> 0 G Q endobj Q endobj q /ID [] >> stream /Type /XObject stream 0.51 Tc 27 0 obj q /Meta1 Do endobj >> Percentage decrease is found by dividing the decrease by the starting number, then multiplying that result by 100%. ET /Meta7 18 0 R 1.005 0 0 1.007 102.382 653.441 cm (-4) Tj Q 339 0 obj /Meta389 Do /Leading 150 endstream 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 /ProcSet[/PDF] 0.737 w /FormType 1 q 1 i /Matrix [1 0 0 1 0 0] Q q 0 g >> /BBox [0 0 15.59 16.44] /Subtype /Form /Subtype /Form /BBox [0 0 88.214 35.886]
Product Manager Meta Interview,
Why Don't I Like Being Touched By My Husband,
How Much Did Velocicoaster Cost,
Articles T
